(x^2+4x+4)(x+2)=0

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Solution for (x^2+4x+4)(x+2)=0 equation:


Simplifying
(x2 + 4x + 4)(x + 2) = 0

Reorder the terms:
(4 + 4x + x2)(x + 2) = 0

Reorder the terms:
(4 + 4x + x2)(2 + x) = 0

Multiply (4 + 4x + x2) * (2 + x)
(4(2 + x) + 4x * (2 + x) + x2(2 + x)) = 0
((2 * 4 + x * 4) + 4x * (2 + x) + x2(2 + x)) = 0
((8 + 4x) + 4x * (2 + x) + x2(2 + x)) = 0
(8 + 4x + (2 * 4x + x * 4x) + x2(2 + x)) = 0
(8 + 4x + (8x + 4x2) + x2(2 + x)) = 0
(8 + 4x + 8x + 4x2 + (2 * x2 + x * x2)) = 0
(8 + 4x + 8x + 4x2 + (2x2 + x3)) = 0

Combine like terms: 4x + 8x = 12x
(8 + 12x + 4x2 + 2x2 + x3) = 0

Combine like terms: 4x2 + 2x2 = 6x2
(8 + 12x + 6x2 + x3) = 0

Solving
8 + 12x + 6x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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